oracle select oldest partition
I gave you a full example, where is yours? For example if I have a query like Select Col1, Col2, RANK() OVER(PARTITION BY Col1 order by Col3 desc) as rank from table1 Thanks in advance Version: 12.1. Here are a few wrong and correct ways to do it. dropping and adding partitions periodically TomWe have a procedure p which drops a partition and adds a partition to a partitioned table t every day, and then the current days data from table t1 is inserted into t( we are not doing exchange partitions due to some business conditions, the table t is being inserted records via a trigger). 5 AND PART_HV_TO_DATE(TABLE_OWNER, TABLE_NAME, PARTITION_NAME) = ( Viewed 1000+ times Purpose . i disagree with your above comments, I would (do) partition the table, purging like that at the year end using DML is not a good idea -- no. Or if video is more your thing, check out Connor's latest video and Chris's latest video from their Youtube channels. Index partitions have the same name as the table partitions only if the indexes are on place when the new partition is created. Dropping Partitions. 4 AND TABLE_NAME = 'EXAMPLE' I am having a similar issue. Remote DBA. There is no archiving requirement but the history table (table B) is required to retain data for 36 months. Just learned that oracle has provided it now... interval partitioning...sry... Is Automatic partitioning available in ORA 10.2? I was testing a new scheduler job in Oracle that calls a shell script on the Linux server. Regarding the customer context, I used some management scripts that include this time dropping oldest partition. I'd like to know what are the options to do this in Oracle Standard Edition which does not have partitioning option. Magically migrate from place to place??? Fill in your details below or click an icon to log in: You are commenting using your WordPress.com account. Oracle Database - Enterprise Edition - Version 11.2.0.1 to 11.2.0.3 [Release 11.2]: Wrong Results (or No Rows) with Full Partition-wise Join Between Reference Partit or the partition id - lots of ways to see what is the oldest partition and what data is in it. If it is, please let us know via a Comment, http://docs.oracle.com/docs/cd/B10501_01/server.920/a96536/ch44.htm#288033, http://www.oracle.com/technology/documentation/oracle7.html, http://docs.oracle.com/docs/cd/B19306_01/server.102/b14231/partiti.htm#sthref2710, http://docs.oracle.com/docs/cd/B28359_01/server.111/b28279/chapter1.htm#FEATURENO07076. Never seen anything like this for this kind of a situation. add partition, drop partition, drop partitions older than N days and so on. AND PART_HV_TO_DATE(TABLE_OWNER, TABLE_NAME, PARTITION_NAME) = ( 3 WHERE TABLE_OWNER = 'ZEDDBA' FROM DBA_TAB_PARTITIONS P unique indexes cannot be skipped. If you want to yield date type information, then you store date-type info in the partition name. Oracle database server 11.2.0.2. Just a simple DDL operation? When you partition a table, you logically split it into many sub-tables. The first step in the job is to truncate the existing parition for the month before loading. Change ), You are commenting using your Facebook account. When do you want to use it? you would have to use partitioned views - still supported, used and available but last documented in 7.3 :). When multiple rows share the same rank the next rank in the sequence is not consecutive. Here is a look … If an Oracle partition is dropped and a row is inserted that would have belonged to the Oracle dropped partition, the row will be stored in the next higher partition. Oracle SQL: select first n rows / rows between n and m (top n/limit queries) At times, it's necessary to select the first n rows or the rows between n and m (paging) from a table or query. Automatic Partition Management for Oracle 10g If you have a moving window partitioning scheme then you should know that in Oracle 11g you now have a brand new way of creating new partitions. 2 FROM DBA_TAB_PARTITIONS P This is inspite of doing 'alter session set skip_unusable_indexes=true'. If you did not like that naming convention, you could substr out the date part of the name and sort on to_date() of that. Each row will assign to a single partition via this partition key and it will store on this partition. SELECT, SQL> SELECT PARTITION_NAME Our requirement is that we dynamically add partition. Does the figure 30 include the max value partition. How about 10? SELECT d.Name "Department", a.Name "Employee", a.Salary "Salary" FROM ( SELECT RANK OVER (PARTITION BY DepartmentId ORDER BY Salary DESC) AS rank, Salary, Name, DepartmentId FROM Employee ) a JOIN Department d ON a.DepartmentId = d.Id WHERE a.rank = 1 ORDER BY "Salary"; In Oracle 11g, you can merge the content of two partitions only in single DDL. We also had two versions of the same SQL statement, one that explicitly specifies the partition name in the FROM clause and one that uses a selective WHERE clause predicate to prune the data set down to just 1 partition. I have a job which runs multiple times in a month. you need to remove all of the commits perhaps? Is this answer out of date? Post was not sent - check your email addresses! How will you handle the same problem, if each day has 2 partitions attached to it. For those who (myself included) are finding it difficult to wrap our minds around the logic behind Tom's original query: you have to put the dates in there -- you have to have a constant date in there. Here is my oracle query. The basic description for the RANK analytic function is shown below. Sorry, your blog cannot share posts by email. What part are you "missing"? Is this still the best method to use for doing a 'rolling window' in 9.2? How will your query handle it. The oldest partition in RO schema is max. There is now a row in the oldest partition in each table. Interval partitioning is enabled in the table's definition by defining one or more range partitions and including a specified interval. define "week" first - there are quite a few definitions for it. put the datafiles in /hey-i-am-not-fs-03/ and /hey-i-am-not-fs-04/. As to the logic of this scenario the partition to be exchanged will probably the oldest one in the actual table but the newest one in the archive table. there is no "rolling window" command as yet (doubt there will be - sort of "implementation dependent"), Tom, would the following query work for finding what partitions to drop? The Select count(*) can be done with a WHERE clause that uses the column(s) that are being used to partition the table. It is not very complex. I have a driver table (with plus 2000 tables, all interval partitions) each table has own RETENTION_DURATION (yes last question in Forum). In 10g I was having a partition name with the date and hour attached to partition name and it was easy to generate a dynamic script to drop partitions older than two days. We didn’t care about data oldest than 2 years. Once an hour we drop the oldest partition in the table as a new partition is added. (3 replies) Hi, Is there a way to get the oracle's rank() over partition by queries in postgresql? :). I cannot believe so many "Oracle developers" are actually questioning the sorting of YYYYMMDD and wasting Tom's time. Some reasons the automated process fails to add the additional partition I was worried about apps failing but, I guess I have to have more bells and whistles in the process to raise a visible flag,kinda, in case of failure. In response of the original question in this thread ..will not the getting a partition for which partition_position (a column in user_tab_partitions and many other partition related views) is max will solve the purpose....that is if someone want to add a partition periodically or drop a partition ...why can not we use partition position - i guess it is a sequentially assigned number in the order partitions are, it depends entirely on how they partition the data and whether the partition boundaries "sort" or not - in geneneral the answer is "probably yes" - but if they partition using MM for example ( and just keep rotating around ). Thanks Martina... a) when one wants to take two existing, adjacent partitions and make them become a single partition (I know, obvious). you have a partition that is 5 terabytes in size? BTW, the partition is on a timestamp column. Automatic Data Optimization Policies are automatically applied to tables Oldest Data Most Recent Data Policy 1 Policy 2 After 180 days of no modification, the oldest partition is identified to be compressed using Hybrid Columnar compression Oracle 12c ILM 20. Tried indexing this column and same results. Imagine it is time to purge the data, and you want to drop the oldest partition. The PARTITION BY indicates it should restart at 1 every time the value of Val changes and we want to order rows by the smallest value of Kind. I want my (range) partitioning scheme to be such that it stores 30 (business)"daily" partitions and 24 "monthly" partitions. I would create a stored procedure to do this personally. You can specify a single partition key or a range of partition keys. 29. Change ), You are commenting using your Google account. Interval partitioning can simplify the manageability by automatically creating the new partitions as needed by the data. adding an empty partition to the end should be a very fast, low impact operation. BC Remote Oracle Support. Change ), You are commenting using your Twitter account. RANK OVER ( [query_partition_clause] order_by_clause ) This is a little more complicated than many other Oracle functions, but I’ll explain the function in this article. Basically what Tom is suggesting is naming scheme where the name contains information that is important to you for partition maintenance. Either way, the partition id's are renamed to keep this in sync when partitions are split/added/dropped etc. Oldest; 0. you would just query based on a template like that -- yes. To partition any table, it should has proper column or columns to select these for partitioning key. EXECUTE IMMEDIATE 'SELECT ' || l_high_value || ' FROM dual' INTO l_date; SELECT PARTITION_NAME It takes 2 to 3 minutes for the quesry inspite of tables and index analyzed properly as well as parameters like index_cost_adj and other being set in INIT.ORA and we wanted to avoid any hints in the any query of the application. WHERE TABLE_OWNER = 'ZEDDBA' Oracle directs insert, update, and delete operations automatically to appropriate partition via … Our "production" table is complete and contains at least one partition that's old enough to archive. Tom I have a table partition by range using date. use an autonomous transaction and it will not affect your current transaction. However, in Oracle 12c, you can merge multiple partitions into one in a single DDL statement. Mihajlo Tekic If I understand correctly you are planning to exchange a partition with a global temporary table.I'm afraid such an attempt would fail with "ORA-14132: table cannot be used in EXCHANGE" SQL> host oerr ora 14132 14132, 00000, "table cannot be used in EXCHANGE" // *Cause: An attempt was made to issue an ALTER TABLE EXCHANGE PARTITION | // SUBPARTITION command, but the … When your needs say "we didn't need, want, desire two partitions there, we want to get rid of one of them". Purpose. you would have to script this - you seem to know the technique well enough. If you exchange the oldest partition of your table there is a risk that it includes data which is older than expected. By having it year-first/then-month/then-day etc, then you can sort in "date order". If anyone is interested, I have a PL/SQL package that will help automate the process of rolling date range partitions off and on. The Table which is populated is paritioned by date and I am using Interval paritioning 11g new feature. For ease of access, script below (please check Tim’s blog for updates and always ask for permission if you’re going to quote ): With this you can get the oldest interval partition by running the following SQL: And the newest interval partition by running the following SQL: 8th July 2017, changed the query so the sub-query join onto the parent query to avoid having to set the predicates in the sub-query. according to the month and the year. can you explain this corelated subquery step wise. For example, consider the following table: create table pos_data ( start_date DATE, store_id NUMBER, inventory_id NUMBER(6), qty_sold NUMBER(3) ) PARTITION BY RANGE (start_date) INTERVAL(NUMTOYMINTERVAL(1, 'MONTH')) ( PARTITION po… It seems much simpler than what's show in your first response, at least to me. I attempted to get it published in Oracle Magazine, but no such luck. if a single day has say 2 partitions, and you have to drop both of them. and the corresponding add partition command? if you plan on doing this lots - you would create unique/primary key constraints as DEFERRABLE (will use NON-unique indexes) and then they can be skipped. If part or all of the result of a SELECT statement is equivalent to an existing materialized view, then Oracle Database may use the materialized view in place of one or more tables specified in the SELECT statement. of course, look at your partition clause, every day the data is supposed to do what? Is this expected? It is not a part of the question, but what if it is so.. One easy way of identifying the "oldest" partition is that it is always has a partition_id of 1 (or is zero?). Get real Remote DBA experts, call BC Remote DBA today. -- Description : Create a function to turn partition HIGH_VALUE column to a date. Now since the parition name is generated by system, I am not able to query the parition dynamically so i could truncate the parition. FROM user_segments ORDER BY segment_Type, segment_name, partition_name; save segsize . I used your example in partitioning a table and was able to get desired results. If the highest Oracle partition is dropped, the insert will fail because the range of values represented by the Oracle dropped partition is no longer valid for the table. Oracle 11g creates the partitions in an automatic fashion, so that when the row arrives at the table, if the partition does not exist, Oracle will create it. The number of rows is not really a good indication of "SIZE". Yep, thats correct. The contents of this blog is from my experience, you may use at your own risk, however you are strongly advised to cross reference with Oracle documentation and to test before deploying to production environments. -- Notes : Has to re-select the value from the view as LONG cannot be passed as a parameter. Since partition names are always in the context of a specific table, there is no harm in giving them generic names like part_yyyymmdd, right? OK I set that partition unusable, now surprisingly, when I load that partition, I get ORA-1502! I posted this on Metalink as well. ( Log Out /  And of course, keep up to date with AskTOM via the official twitter account. But what if you want the top-N rows in each group? 12c - row limiting clause. If the WOS contains data for the target table, DROP_PARTITIONS first invokes a moveout operation. There's no native syntax for this in SQL. Use the DROP_PARTITIONS function to drop one or more partition keys for a given table. ( Log Out /  Reason is that you are trying to delete from view instead of deleting from the underlying base table. So for example, if you partition on a column called PROCESSED_DATE then you could do Select count(*) from schema.mytable WHERE PROCESSED_DATE BETWEEN 01/01/2009 and 06/01/2009 I was required to find the oldest and newest interval partition to be able to do some automated maintenance, but found query USER_TAB_PARTITIONS, ALL_TAB_PARTITIONS and DBA_TAB_PARTITIONS was a bit tricky as the HIGH_VALUE is a LONG data type :( A quick search on the web and I found a perfect solution from my good friend… Great interactive discussion and great site. Some time ago, I had to deal with a new partitioning scenario that included sliding windows stuff for mainly archiving purpose. Delete All Rows in a Partition Fast. CREATE OR REPLACE FUNCTION part_hv_to_date (p_table_owner IN VARCHAR2, -- -----------------------------------------------------------------------------------, -- File Name : https://oracle-base.com/dba/miscellaneous/part_hv_to_date.sql. ... to be the most intuitive.. and doesn't require me to learn what partition by is all about. This blog reflect my own views and do not necessarily represent the views of my current or previous employers. i.e. The analytic clause is described in more detail here.Let's assume we want to assign a sequential order, or rank, to people within a department based on salary, we might use the RANK function like this.What we see here is where two people have the same salary they are assigned the same rank. and so you see they are not sortable right? I guess one option would be to work using the partition position. Luckily Oracle Database has a couple of other tricks available. WITH ORDERED AS ( SELECT ID , Val , kind , ROW_NUMBER() OVER (PARTITION BY Val ORDER BY Kind ASC) AS rn FROM mytable ) SELECT ID , Val , Kind FROM ORDERED WHERE rn = 1; For example, the three most recent orders for each customer? Change ). #b"If you have lots of partitions to manage you might find easier to merge the table name with the partition_name (eg MYTABLE_yy_ddd or whatever) - it gives the potential of checking that you are about the drop the correct partition of. AND TABLE_NAME = 'EXAMPLE' I was required to find the oldest and newest interval partition to be able to do some automated maintenance, but found query USER_TAB_PARTITIONS, ALL_TAB_PARTITIONS and DBA_TAB_PARTITIONS was a bit tricky as the HIGH_VALUE is a LONG data type , A quick search on the web and I found a perfect solution from my good friend Tim Hall (Oracle Base), who created a function to convert the LONG into a DATE by executing the HIGH VALUE . The issue that I am facing is related to system generated partition names in 11g. Last updated: August 13, 2019 - 3:55 pm UTC. I have been to your site once and I'm hooked for life. DDL does not do binds (it is not shareable, nor reusable so it is OK). I'd rather rely on a naming convention personally. no, an exchange involves NO MOVEMENT OF DATA. run that and you'll find it never ever returns any rows. Great thread! ( Log Out /  The idea is to create a partitioned table B which will be populated on a monthly basis from table A. I want to create a process that will create a partition each month before inserting the data from table A into table B( I am not planning on to do exchange partition since the data on table A is still required to be there until the next month). -- Create partition function and scheme CREATE ... (PartCol) ON myPartitionScheme(PartCol) GO -- Polulate table data DECLARE @x INT, @y INT SELECT @y=3 WHILE @y < 10 BEGIN SELECT @x=1 WHILE @x < 20000 ... As you can see from the query results we have 7 partitions in this table and we would like to remove the oldest partition. I cannot imagine what problem you ran into prior to this, but never use the sys objects dirctly. If you are new to partitioning, check out Connor McDonald's introduction series here. If you found this blog post useful, please like as well as follow me through my various Social Media avenues available on the sidebar and/or subscribe to this oracle blog via WordPress/e-mail. For example, the table shown in Partitioning a New Table is partitioned by column order_date: this sort method has become very popular since y2k efforts required the need for the yyyy...i would like to see someone prove that it doesn't work...tom...great site! What's the most efficient way to achieve rolling windows implementation without using partitioning? all partitioned tables will have the same partition name for say 1/1/2004 (part_20040101). well, that is an administrative problem you have to sort of come up with a solution for. Active Oldest Votes. give me a for example cut and paste, just like this: I am not going to use cursor_sharing=exact in the program. select * from co.orders order by order_datetime desc fetch first 10 rows only; Or if you're using an archaic version of Oracle Database you can use the rownum trick. This gives an easy, fast way to remove all the rows in a partition… SELECT PARTITION_NAME, TABLESPACE_NAME, NUM_ROWS FROM USER_TAB_PARTITIONS WHERE PARTITION_NAME='P1' ... BC is America's oldest and largest Remote DBA Oracle support provider. Send me an e-mail at Joseph_C_Szoke@KeyBank.Com, if you are interested. I am planning to write a pakage containing dynamic SQL for all the partition management stuff i.e. Enter your email address to follow this blog and receive notifications of new posts by email. Consider a table range partitioned (on a date column), Requirement 1: 'why not just insert /*+ append */ into ME select from m01; drop partition m01;'. /* Write your PL/SQL query statement below */ SELECT distinct Num as ConsecutiveNums FROM ( SELECT Id, Num, lead (ID, 2, -1) OVER (PARTITION BY Num ORDER BY id) AS id2 FROM Logs) a WHERE a.id2 = a.id + 2 -- part_hv_to_date(a.table_owner, a.table_name, a.partition_name) as high_value. Why not use some PL/SQL in maintaining your range-based. why all of the commits if this need be atomic. In my opinion only a date column can sort like that, not a varchar2 column. The parameters of the RANK function are different, depending on whether you’re using it as an aggregate or analytical function Connor and Chris don't just spend all day on AskTOM. I have a partition table which is partitioned every hour and we need to keep only two days of data in the table. PART 2 - Unplug the oldest partition . Simple, just drop the child partition, and then the parent partition, and all will be good - or will it? yes, exact is the only setting i would permit in an init.ora parameter file. I'm confused as to why you want to merge m01 and me. you can size rollback, or you can do a point in time restore, or you can get 10g with flashback database... this is a pretty simple script..... You can do it, I am sure.
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